Answer:
the other guy is implying the answer is D i think.
D.) ∠CAB ≅ ∠EDB, ∠ACB ≅ ∠DEB.
The given proof is the triangle proportionality theorem which states that
the segments formed by side DE are proportional.
Reasons:
The proof is to show that (AD)/(DB) = (CE)/(EB)
The two column proof is presented as follows;
Statement [tex]{}[/tex] Reason
1. [tex]\overline{DE} \parallel \overline{AC}[/tex] [tex]{}[/tex] 1. Given
2. ∠CAB ≅ ∠EDB [tex]{}[/tex] 2. Corresponding angles formed between ║ lines
3. ΔABC ~ ΔDBE [tex]{}[/tex] 3. AA criterion for similarity
4. [tex]\underline{(AB)/(DB) = (CB)/(EB) }[/tex] [tex]{}[/tex] 4. Corr. sides of similar Δs are prop.
5. AB = AD + DB [tex]{}[/tex] 5. Segment addition
CB = CE + EB
6. (AD + DB)/(DB) = (CE + EB)/(EB) [tex]{}[/tex] 6. Substitution Property of Equality
7. (AD)/(DB) + 1 = (CE)/(EB) + 1 [tex]{}[/tex] 7. Division
8. (AD)/(DB) = (CE)/(EB) [tex]{}[/tex] 8. Subtraction Property of Equality
The probable missing statement which is statement 4 as obtained from a similar question online in the proof is; [tex]\underline{(AB)/(DB) = (CB)/(EB) }[/tex]
The reasons are;
Statement 2; If two parallel lines are cut by a transversal, the corresponding angles are congruent.
Statement 3; Angle Angle, AA, similarity criteria
Statement 4; Corresponding sides of similar triangles are proportional
Learn more about triangle proportionality theorem here:
https://brainly.com/question/2078223
