Answer:[tex]F_c=9.375 N[/tex]
Explanation:
Given
mass of body [tex]m=2 kg[/tex]
radius of circle [tex]r=3 m[/tex]
Time Period [tex]T=5 s[/tex]
suppose [tex]\omega [/tex]is the angular velocity of revolution
therefore [tex]\omega T=2\pi [/tex]
[tex]\omega =\frac{2\pi }{5}=1.25 rad/s[/tex]
Centripetal acceleration [tex]a_c=\omega ^r[/tex]
[tex]a_c=1.25^2\times 3[/tex]
[tex]a_c=4.68 m/s^2[/tex]
therefore centripetal [tex]F_c=m\omega ^2\times r[/tex]
[tex]F_c=9.375 N[/tex]
