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Jolene invests her savings in two bank accounts, one paying 4 percent and the other paying 10 percent simple interest per year. She puts twice as much in the lower-yielding account because it is less risky. Her annual interest is 3996 dollars. How much did she invest at each rate?

Respuesta :

Answer:

$ 22200 in higher yielding bank and $ 44400 in lower yielding bank

Step-by-step explanation:

       Jolene invests in two bank accounts. The first account gives a 4% interest per year and the second bank gives a 10% interest rate per year.

       She puts twice as much in the lower yielding bank account. Let us denote the amount put in high yielding bank account by [tex]x[/tex]. Lower yielding bank account will have [tex]2x[/tex].

       [tex]Interest\text{ }per\text{ }year=Principal\times Interest\text{ }rate[/tex]

Interest from lower yielding bank = [tex]\dfrac{4}{100} \times 2x=\dfrac{8x}{100}[/tex]

Interest from higher yielding bank = [tex]\dfrac{10}{100} \times x=\dfrac{10x}{100}[/tex]

Total Interest per year = $ 3996 = [tex]\dfrac{8x}{100} +\dfrac{10x}{100}=\dfrac{18x}{100}[/tex]

[tex]x=22200 \$[/tex]

Jolene invested $ 22200 in higher yielding bank and $ 44400 in lower yielding bank.