1) Distance: 9 m, displacement: +5 m
2) The average speed is 3 m/s
3) The average velocity is +2 m/s
Explanation:
1)
We start by reminding the definitions of distance and displacement:
- Distance: it is the total length of the path covered by an object, regardless of the direction of motion
- Displacement: is the distance in a straight line between the initial position and final position of motion
Let's now analyze the motion represented in the figure:
Initial position: [tex]x_0 = -1 m[/tex]
Intermediate position: [tex]x_1 = +6 m[/tex]
Final position: [tex]x_2 = +4 m[/tex]
Therefore, the distance covered is
[tex]distance = |x_1-x_0|+|x_2-x_1|=|+6-(-1)|+|+4-(+6)|=7+2=9 m[/tex]
While the displacement is:
[tex]displacement = x_2 - x_1 = +4 - (-1) = +5 m[/tex]
2)
The average speed is a scalar quantity defined as
[tex]speed=\frac{d}{t}[/tex]
where
d is the distance travelled
t is the time taken
For the object in this problem,
d = 6 m
t = 2 s
Substituting, we find the average speed:
[tex]speed = \frac{6 m}{2 s}=3 m/s[/tex]
3)
The average velocity is a vector quantity defined as
[tex]velocity = \frac{d}{t}[/tex]
where
d is the displacement
t is the time interval
For the object in this problem,
d = +12 m
t = 6 s
Substituting, we find the average velocity:
[tex]velocity=\frac{+12 m}{6s}=+2 m/s[/tex]
Where the positive sign + indicates the direction of the velocity vector.
Learn more about average speed and average velocity:
brainly.com/question/8893949
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