Respuesta :
Answer:
The points which satisfy the given line equation may be ( 0 , - 15 ) , or ( [tex]\frac{15}{11}[/tex] ,0 ) , depends on what value we are taking .
Step-by-step explanation:
Given equation of line is
y = 11 x - 15
Since , The standard equation of line is
y = m x + c , where m is the slope of line and c is constant
here given equation of line is y = 11 x - 15
so , slope of this line is m = 11
Let ( x, y ) is the points on the line , which satisfy the line equation
so, let x = 0 , put the x value in given line equation
y = 11 × 0 - 15
Or, y = 0 - 15
∴ y = - 15
so, points is ( x , y ) = ( 0 , - 15 )
Again , Let y = 0 , put the y value in given line equation
0 = 11 x - 15
or, 0 + 15 = 11 x
Or, 15 = 11 x
∴ x = [tex]\frac{15}{11}[/tex]
so, points is ( x , y ) = ( [tex]\frac{15}{11}[/tex] , 0 )
Hence The points which satisfy the given line equation may be ( 0 , - 15 ) , or ( [tex]\frac{15}{11}[/tex] ,0 ) , depends on what value we are taking . Answer
