A hammer slides down a roof that makes a 30.0°angle with the horizontal. What are the magnitudes of the components of the hammer's velocity at the edge of the roof if it is moving at a speed of 8.25 m/s

Respuesta :

Answer:7.14[tex]ms^{-1}[/tex],4.125[tex]ms^{-1}[/tex]

Explanation:

Whenever an object is moving in a 2D frame,its motion can be analysed as if it is travelling in two independent 1D frames.

One of such independent 1D frames are along horizontal and another along vertical.

Let [tex]v[/tex] be the total velocity.

Given that,[tex]v=8.25ms^{-1}[/tex]

We call the horizontal velocity as [tex]v_{h}[/tex] and the vertical velocity as [tex]v_{v}[/tex].

[tex]v_{h}[/tex]=[tex]vCos\alpha[/tex]

[tex]v_{v}=vSin\alpha[/tex]

where [tex]\alpha[/tex] is the angle between the object and horizontal.

It is given that [tex]\alpha =30^{0}[/tex]

[tex]v_{h}=8.25\times Cos(30^{0})=7.14ms^{-1}[/tex]

[tex]v_{v}=8.25\times Sin(30^{0})=4.125ms^{-1}[/tex]