The angle of elevation is 13.5 degrees approximately
Given that , The length of a flagpole is 12cm
A student stands 50 m from the foot of the flagpole
Now, we have to observe that, above situation forms a right angle triangle with base 50 m and height of 12 m.
Then, we can apply,
[tex]\tan \theta=\frac{\text {opposite side}}{\text {adjacent side}}[/tex]
where [tex]\theta[/tex] is angle of elevation and opposite side is height and adjacent side becomes base
[tex]\begin{array}{l}{\text { So, } \tan \theta=\frac{12}{50}} \\\\ {\theta=\tan ^{-1}\left(\frac{12}{50}\right)} \\\\ {\theta=13.495}\end{array}[/tex]
Hence, the angle of elevation is 13.5 degrees approximately.
