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A king decided to share his collection of precious rubies with his three daughters. He gave his oldest
daughter, Clara, 20% of the rubies. He gave Harriet, his middle daughter, 25% of those that were left. He
gave his youngest daughter, Melissa, 30% of the remaining rubies. After each daughter had received her
share, the king saw that there were 21 rubies left in his collection,
FET 75%
How many rubies did the king have in his collection to begin with?
How many did each daughter receive?

Respuesta :

StarGazers

Suppose king has 100% of rubies and he decided to give 20% away so he's left with 80%. After that he decided to give 25% of 80% so he's left with 60% of the total rubies. Moreover he distributed 30% of the 60% he had finally he has only 42% of the original left with him that totalled to 21

42x/100=21

x=50

King had total 50 rubies

First daughter share= 50*20%= 10

Second daughter share= 40*25%= 10

Third daughter share= 30*30% = 9

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