Answer:
Change in gravitational potential energy of the chair is, [tex]\Delta PE=390\ J[/tex]
Explanation:
It is given that,
Mass of the chair, m = 12 kg
Distance of the second floor from the ground, h = 3.3 m
The position of ground at h = 0
Let [tex]\Delta PE[/tex] is the change in gravitational potential energy of the chair. Initial potential f the chair is equal to 0.
[tex]\Delta PE=mgh[/tex]
[tex]\Delta PE=12\ kg\times 9.8\ m/s^2\times 3.3\ m[/tex]
[tex]\Delta PE=388.08\ J[/tex]
or
[tex]\Delta PE=390\ J[/tex]
So, the change in the gravitational potential energy of the chair is 390 joules.
