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Consider the graph of the line y = -x-4 and the point
(-4,2).
The slope of a line parallel to the given line is
A point on the line parallel to the given line, passing
through (-4,2), is
The slope of a line perpendicular to the given line is
A point on the line perpendicular to the given line
passing through (-4, 2), is

Respuesta :

SouthernRider

Answer:

-1

y = -x -2

1

y = x + 6

Step-by-step explanation:

Given line is y = - x - 4

We know that the equation of a line is of the form y = mx + c where m is the slope of the line and c is a constant

Now The slope of the given line is m = -1

We know that the slope of any line parallel to the given line is same the original one

Therefore the slope of the line parallel to the given line is -1

Given the point is ( -4 , 2 ) and slope is  -1

We know that the equation of a line passing through the point (c , d) and slope m is

[tex]y - d=m\times(x-c)[/tex]

Here the equation is

[tex]y-2=-1\times(x-(-4))[/tex]

y = -x -2

We know that if two lines with slopes m1 and m2 are perpendicular then m1m2 = -1

Here m1 = -1 then

m2 = 1

Given the point is ( -4 , 2 ) and slope is  1    

We know that the equation of a line passing through the point (c , d) and slope m is

[tex]y - d=m\times(x-c)[/tex]

Here the equation is

[tex]y-2=1\times(x-(-4))[/tex]

y = x + 6

haleycaraway2

Answer:

1/2

(0,4)

-2

(-2,-2)

Step-by-step explanation:

edge

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