Explanation:
It is given that,
Mass of the ball, m = 0.06 kg
Initial speed of the ball, u = 56 m/s
Final speed of the ball, v = -34.5 m/s (opposite direction)
(a) Let J is the impulse delivered to the ball by the racquet. It is equal to the change in momentum of the object as :
[tex]J=m(v-u)[/tex]
[tex]J=0.06\ kg(-34.5\ m/s-56\ m/s)[/tex]
J = -5.43 kg-m/s
(b) The work done by the racquet on thee ball is equal to the change in kinetic energy as :
[tex]W=\dfrac{1}{2}m(v^2-u^2)[/tex]
[tex]W=\dfrac{1}{2}\times 0.06((-34.5)^2-(56)^2)[/tex]
W = -58.372 Joules
