Respuesta :
Answer:
The correct expression is: [tex]\frac{n^3}{9}-6+12[/tex]
One of the step to determining the value when [tex]n=3[/tex] is [tex]3-6+12[/tex]
The value when [tex]n=3[/tex] is [tex]9[/tex].
Step-by-step explanation:
Six less than the quotient of a number cubed and nine, increased by twelve.
Let the number be [tex]=n[/tex]
The mathematical expression of the statement can be written as:
[tex]\frac{n^3}{9}-6+12[/tex]
Evaluating the expression when [tex]n=3[/tex]
[tex]=\frac{3^3}{9}-6+12[/tex]
[tex]=\frac{27}{9}-6+12[/tex]
[tex]=3-6+12[/tex]
[tex]=9[/tex]
∴ The value when [tex]n=3[/tex] is [tex]9[/tex].
Answer:
( A ) The correct expression is 6 minus StartFraction n cubed Over 9
EndFraction + 12.
( D ) One of the steps to determining the value when n = 3 is 6 minus 3 + 12.
( F ) The value when n = 3 is 9.
Step-by-step explanation:
