Answer:
[tex]a=2.22\ m/s^2[/tex]
Explanation:
Mass of the boy, m = 62 kg
Mass of the girl, m' = 46 kg
The acceleration of the girl toward the boy is, [tex]a'=3\ m/s^2[/tex]
The force acting on the girl is given by :
[tex]F'=m'\times a'[/tex]
[tex]F=46\ kg\times 3\ m/s^2[/tex]
F' = 138 N
Let a is the magnitude of the acceleration of the boy toward the girl. Again using the second law of motion to find it as :
[tex]a=\dfrac{F'}{m}[/tex]
[tex]a=\dfrac{138\ N}{62\ kg}[/tex]
[tex]a=2.22\ m/s^2[/tex]
So, the the acceleration of the boy toward the girl is [tex]2.22\ m/s^2[/tex].
