Answer:
Probability of choosing a black pair of pants and shoes [tex]= \frac{6}{91}[/tex]
Step-by-step explanation:
Given:
Total number of pants Mike has =[tex]\textrm{ 3 tan pants + 5 jeans + 2 black pants + 3 gray pants = 13 pair of pants} [/tex]
Probability of randomly choosing a pair of black pants = [tex]\frac{\textrm{Number of Black pants}}{\textrm{Total number of pants}} = \frac{2}{13}[/tex]
Total number of shoes Mike has = [tex]\textrm{ 2 brown shoes + 3 black shoes + 2 blue shoes = 7 pairs of shoes} [/tex]
Probability of randomly choosing a pair of black shoes = [tex]\frac{\textrm{Number of Black shoes}}{\textrm{Total number of shoes}} = \frac{3}{7}[/tex]
Probability of choosing a black pair of pants and shoes = Â [tex]\frac{2}{13}\times \frac{3}{7} = \frac{6}{91}[/tex]
