Answer:[tex]4.25\times 10^{16}[/tex]
Explanation:
Let [tex]e[/tex] be the charge of each electron in coloumbs.
Let the given charge be [tex]x[/tex] in coloumbs.
The number of electrons lost or gained by a [tex]x[/tex][tex]C[/tex] is [tex]\frac{x}{e}[/tex].
As we know,the charge of electron is a constant and is equal to [tex]1.6\times 10^{-19}C[/tex]
So,[tex]e=1.6\times 10^{-19}C[/tex]
Given,[tex]x=6.8\times 10^{-3}C[/tex]
The number of electrons lost or gained by a [tex]6.8milli[/tex][tex]C[/tex] is [tex]\frac{6.8\times 10^{-3}}{1.6\times 10^{-19}}[/tex]=[tex]4.25\times 10^{16}[/tex]
