Answer:
1.18 Ć 10ā· c
Iron is the anode and zinc is the cathode.
Explanation:
Let's consider the reduction of Zn²āŗ.
Zn²āŗ(aq) + 2 eā» ā Zn(s)
How many coulombs of charge are needed to produce 61.2 mol of solid zinc?
We can establish the following relations:
Then, for 61.2 mol of Zn:
[tex]61.2molZn.\frac{2mole^{-} }{1molZn} .\frac{96468c}{1mole^{-}} =1.18 \times 10^{7} c[/tex]
Identify the anode and cathode when plating an iron nail with zinc.
The anode is where the oxidation takes place and the cathode is where the reduction takes place.
Anode (oxidation): Fe(s) ā Fe²āŗ(aq) + 2 eā»
Cathode (reduction): Zn²āŗ(aq) + 2 eā» ā Zn(s)