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Numbers from zero to nine are individually selected at random and combined to make a code that contains a six-digit number. Numbers can be repeated. If you were given ten tries to guess the code what would be the probability of guessing the correct code? Give you answer as a fraction. Do not include commas in your answer, for example, 31,000 would be written as 31000.

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Answer:

The probability of guessing the correct code is [tex]\frac{1}{100000}[/tex] ,  If you were given ten tries to guess it.

Step-by-step explanation:

First of all, we need to find the total possible combinations due the code is composed by numbers from zero to nine are individually selected at random and combined to make a code that contains a six-digit number. So we obtain [tex]\# of\ possible\ combinations=10^{6}=1000000[/tex].

Then, as we have ten tries to guess, [tex]\frac{\# of\ tries}{\# of\ possible\ combinations} =\frac{10}{1000000}=\frac{1}{100000}[/tex], is the probability of guessing the correct code, one out one houndred thousand.

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