In the xy coordinate plane the slope of line p is 1 2 and its x-intercept is -3. Find the equation of a line that is perpendicular to p and intersects p at is x-intercept. A) y = -2x - 3 B) y = -2x + 3 C) y = -2x - 6 D) y = -2x + 6

Respuesta :

Answer:

Option C) y = -2x - 6

Step-by-step explanation:

The correct question is

In the xy coordinate plane the slope of line p is 1/2 and its x-intercept is -3. Find the equation of a line that is perpendicular to p and intersects p at is x-intercept.

step 1

Find the slope of a line that is perpendicular to p

we know that

If two lines are perpendicular, then their slopes are opposite reciprocal (the product of the slopes is equal to -1)

[tex]m_1*m_2=-1[/tex]

we have

[tex]m_1=\frac{1}{2}[/tex] ----> slope of line p

substitute

[tex](\frac{1}{2})*m_2=-1[/tex]

[tex]m_2=-2[/tex] ----> slope of the line perpendicular to p

step 2

Find the equation of the line  that is perpendicular to p and intersects p at is x-intercept

we have

[tex]m=-2[/tex]

[tex]point\ (-3,0)[/tex]

Find the equation of the line in point slope form

[tex]y-y1=m(x-x1)[/tex]

substitute

[tex]y-0=-2(x+3)[/tex]

[tex]y=-2x-6[/tex]