108J of work was done on a closed sysem. During this phase of the experiment, 79J of heat was added to the system.What was the total change in the internal energy of the system.

Respuesta :

The change in internal energy of the system is +187 J

Explanation:

According to the first law of thermodynamics, the change in internal energy of a system is given by the equation:

[tex]\Delta U = Q + W[/tex]

where

[tex]\Delta U[/tex] is the change in internal energy

Q is the heat absorbed by the system

W is the work done on the system

For the system in this problem, we have

W = +108 J is the work done on it

Q = +79 J is the hear added to it

So, the change in internal energy is

[tex]\Delta U = 108 + 79 = +187 J[/tex]

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