Answer:
The perimeter of the figure is, [tex]68 \dfrac{1}{2}[/tex] yd
Step-by-step explanation:
The perimeter of the figure is,
[tex](10\dfrac{1}{3} + 24\dfrac{1}{4} + 15\dfrac{2}{3} + 18\dfrac{1}{4})[/tex] yd
= [tex]((10+24+15+18)+ (\frac {1}{3} + \frac {2}{3} + \frac {1}{4} + \frac {1}{4}))[/tex] yd
=[tex](67 + 1 + \frac{1}{2})[/tex] yd
=[tex]68 \dfrac{1}{2}[/tex] yd
We know that if there is a polygon with side lengths [tex]a_{i}[/tex] unit ∀
i = 1(1}n where n ∈ N - {1, 2}
then, it's perimeter is given by,
[tex]\sum_{i=1}^{n}a_{i}[/tex] unit
