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On a drive from one city to​ another, Victor averaged 5151 mph. If he had been able to average 7575 ​mph, he would have reached his destination 88 hrs earlier. What is the driving distance between one city and the​ other?

Respuesta :

prozehus

Answer:

d=1.416.525 mile

Step-by-step explanation:

V1=5151m/h, t1=t, V2=7575m/h, t2=t-88h

d1=d2 Because it is same distance; V1=d1/t and V2=d2/(t-88) but d1=d2

d=V1t=V2(t-88) → 5151t=7575(t-88) → 5151t=7575t-666.600 → 7575t-5151t=666.600 → 2424t=666.600 → t=666.600/2424 → t=275h so

[tex]d=5151\frac{mile}{h}.275h =  1.416.525mile[/tex]

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