Answer:
0.028
Step-by-step explanation:
Let sample space, S, be the trucks.
Hence, n(S)= number of trucks=9750
Let E be the event of the truck failing within the first two years of operation.
Hence, n(E)=273
Therefore by classical definition of probability, the probability of occurrence of the event E, denoted by P(E), is
P(E)=[tex]\frac{n(E)}{n(S)}[/tex]=[tex]\frac{number of trucks failed within two years of operation}{Total number of trucks}[/tex]
⇒P(E)=[tex]\frac{273}{9750}[/tex]=0.028
