Does anyone mind helping me with this? It seems simple enough.

The question is: Radical x-3 = radical x + 3 (the +3 is outside of the radical). We are solving for X in this question.

Respuesta :

Answer:

x = 4

Step-by-step explanation:

It is given that [tex]\sqrt{(x - 3)} = \sqrt{x} + 3[/tex], and we have to solve the given equation for x.

Now, we have [tex]\sqrt{(x - 3)} = \sqrt{x} + 3[/tex]

Squaring both sides we get  

[tex][\sqrt{(x - 3)}] ^{2} = [\sqrt{x} + 3]^{2}[/tex]

⇒ x - 3 = x + 6√x + 9 {Since we know the formula of (a + b)² = a² + 2ab + b²}

⇒ 6√x = - 12

√x = -2

Again squaring both sides we get  

⇒x = 4 (Answer)