Basketball star Mumford (a six foot senior forward) places a mirror on the ground x ft. from the base of a basketball goal. He walks backward four feet until he can see the top of the goal, which he knows is 10 feet tall. Determine the how far the mirror is from the basketball goal. Justify your answer.

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Respuesta :

Answer:

6.67 feet

Step-by-step explanation:

The situation is as shown in the figure.

ON is the normal to the mirror at the point of incidence O

⇒ ∠BON = ∠DON = 90°

By the laws of reflection: angle of incidence = angle of reflection :

∠AON = ∠CON

⇒ ∠AOB = ∠COD

tan(∠AOB) = tan(∠COD)

⇒[tex]\frac{AB}{OB}[/tex] = [tex]\frac{CD}{OD}[/tex]

⇒[tex]\frac{6}{4}[/tex] = [tex]\frac{10}{x}[/tex]

⇒x = [tex]\frac{40}{6}[/tex] = [tex]\frac{20}{3}[/tex] = 6.67 ft

∴ Distance of the mirror from basketball goal is 6.67 ft

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