Respuesta :
Answer:
c. 16 black rabbits, 0 white rabbits, 0 gray rabbits.
Explanation:
Let dominant black allele be = B
Let recessive white allele be = b
True breeding rabbit would mean that they are homozygous in their genotype hence true breeding black rabbit will be BB and true breeding white rabbit will be bb.
BB X bb :
  B   B
b Bb  Bb
b  Bb  Bb
All the offspring are heterozygous with one dominant B allele so the phenotype black colour will be produced and all 16 individuals of F1 generation will be black in colour.
Answer:
c. 16 black rabbits, 0 white rabbits, 0 gray rabbits.
Explanation:
I took a test on this once