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A horizontal rod 0.300 m long carries a current through a uniform horizontal magnetic field of magnitude 6.40×10−2 T that points perpendicular to the rod. Part A If the magnetic force on this rod is measured to be 0.140 N , what is the current flowing through the rod?

Respuesta :

Answer:

Current, 7.29 A

Explanation:

It is given that,

Length of the horizontal rod, L = 0.3 m

Magnetic field through a horizontal rod, [tex]B=6.4\times 10^{-2}\ T[/tex]

The magnetic force acting on the rod, F = 0.14 N

Let the current flowing through the rod is given by I. The magnetic force acting on an object in the uniform magnetic field is given by :

[tex]F=ILB\ sin\theta[/tex]

Here, [tex]\theta=90^{\circ}[/tex]

[tex]F=ILB[/tex]

[tex]I=\dfrac{F}{LB}[/tex]

[tex]I=\dfrac{0.14\ N}{0.3\ m\times 6.4\times 10^{-2}\ T}[/tex]

I = 7.29 A

So, the current flowing through the rod 7.29 A.

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