Answer:
Explanation:
Let the clamp be at x distance from the left hand end of rod.
Taking left hand as origin , the formula for centre of mass is
x ( cm ) =[tex]\frac{(m_1\times x_1+m_2\times x_2}{(m_1+m_2) }[/tex]
= [tex]\frac{2.4\times x+1.8\times1}{1.8+2.4}[/tex]
1.2 = [tex]\frac{2.4\times x+1.8\times1}{1.8+2.4}[/tex]
solving
x = 1.35 m
The new center mass of the composite object from the left is 1.35 m.
The postion of the clamp from the left is determined by applying center mass formula ss shown below.
Let the position of the center of gravity of the clamp from left = x
Xcm = (x₁m₁ + m₂x₂)/(m₁ + m₂)
where;
Keep the left end of the rod constant, the center mass of the rod is calculated as
x₂ = (x₀m + x'm)/2m
x₂ = (0 + 2x1.8)/(2x1.8) = 1 cm
Xcm = (x₁m₁ + m₂x₂)/(m₁ + m₂)
1.2 = (2.4x₁ + 1.8x1)/(2.4 + 1.8)
1.2 = (2.4x₁ + 1.8)/(4.2)
2.4x₁ + 1.8 = 5.04
2.4x₁ = 3.24
x₁ = 3.24/2.4
x₁ = 1.35 m
Thus, the new center mass of the composite object from the left is 1.35 m.
Learn more about center mass here: https://brainly.com/question/13499822
