Answer:
The probability that they have a homozygous child is of 0%.
Explanation:
This can be explained with a Punnet square:
Alleles:
Female: Aa
Male: Bb
They are both heterozygous
      A  a
B Â Â Â Â AB Â aB
b    Ab   ab
They have 50% of having one mutation from the A allele and 25% of the allele B.