The right answer is Option D.
Step-by-step explanation:
Let,
Kyle's money = x
Hayden's money = y
Jeremy's money = z
According to statements;
Kyle has three times as much money in his savings account as  Hayden.
x = 3y  Eqn 1
Hayden has twice as much money in his savings account  as Jeremy.
z = 2y  Eqn 2
Combined Kyle, Hayden, and Jeremy have a total of  $612.
x+y+z=612 Â Eqn 3
Putting value of x and z from Eqn 1 and 2 in Eqn 3
[tex]3y+y+2y=612\\6y=612[/tex]
Dividing both sides by 6
[tex]\frac{6y}{6}=\frac{612}{6}\\y=102[/tex]
Putting in Eqn 1;
[tex]x=3(102)\\x=306[/tex]
Kyle has $306 in his account.
The right answer is Option D.
Keywords: Linear equations, division
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