Step-by-step explanation:
Let [tex]w[/tex] be the weight of the second pumpkin.
Given that weight of first pumpkin is [tex]903[/tex] pounds.
Since we need the weight of the second pumpkin to be minimum,the average weight of the two pumpkins must be just equal to the required weight to win.
Given that the required weight to win is [tex]875[/tex] pounds.
So,[tex]875=\frac{w+903}{2}[/tex]
[tex]1750=w+903[/tex]
[tex]w=847[/tex] pounds