The speed of the ball is 1.57 m/s
Explanation:
We start by calculating the angular speed of the ball, which is given by
[tex]\omega = \frac{2\pi}{T}[/tex]
where
T is the period of revolution
For the ball in this problem,
T = 2 s
(since the ball makes 1 revolution every 2 seconds)
So, the angular speed is
[tex]\omega = \frac{2\pi}{T}=\frac{2\pi}{2}=\pi rad/s[/tex]
Now we can calculate the speed of the ball by using
[tex]v=\omega r[/tex]
where
r = 0.5 m is the radius of the circular path
Substituting,
[tex]v=(\pi)(0.5) = 1.57 m/s[/tex]
Learn more about angular motion:
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