Answer:
This solution has a molarity of 3.12 M = 3.12 mol/ L
Explanation:
Step 1: Data given
mass of CH3OH = 30.0 grams
Volume of the solution = 300.0 mL = 0.3 L
Molar mass of CH3OH (see periodic table)
⇒ C = 12 g/mol
⇒ H = 1.01 g/mol
⇒ O = 16 g/mol
⇒ 1*12 + 4*1.01 + 16 = 32.04 g/mol
Step 2: Calculate number of moles of CH3OH
Moles CH3OH = mass CH3OH / Molar mass CH3OH
Moles CH3OH = 30.0 grams / 32.04 g/mol
Moles CH3OH = 0.936 mol
Step 3: Calculate molarity of the solution
Molarity of solution = moles CH3OH / volume of water
Molarity solution = 0.936 mol /0.300 L
Molarity of the solution = 3.12 M
This solution has a molarity of 3.12 M = 3.12 mol/ L
