The motorbike reaches 100 km/h in 3.5 seconds
Explanation:
The motion of the motorbike is a uniformly accelerated motion (= constant acceleration), therefore we can use the following suvat equation:
[tex]v=u+at[/tex]
where
v is the final velocity
u is the initial velocity
a is the acceleration
t is the time
For the motorbike in this problem,
u = 0 (it starts from rest)
[tex]v = 100 km/h = 27.8 m/s[/tex] is the final velocity
[tex]a=7.9 m/s^2[/tex] is the acceleration
Solving for t, we find the time it takes for the bike to reach that velocity:
[tex]t=\frac{v-u}{a}=\frac{27.8-0}{7.9}=3.5 s[/tex]
Learn more about accelerated motion:
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