Answer:
[tex](x-y)\left(y^{2}-4\right) \text { is the product of }-y^{3}+x y^{2}-4 x+4 y[/tex]
Step-by-step explanation:
[tex]\text { Given equation is }-y^{3}+x y^{2}-4 x+4 y[/tex]
[tex]\text { Writing all }^{a} x^{\prime \prime} \text { terms and "y" terms at a place. }[/tex]
[tex]\left(-4 x+x y^{2}\right)+\left(4 y-y^{3}\right)[/tex]
Now take “x” common in the first term and “y” common in second term then the equation becomes as follows:
[tex]x\left(-4+y^{2}\right)-y\left(-4+y^{2}\right)[/tex]
[tex]x\left(y^{2}-4\right)-y\left(y^{2}-4\right)[/tex]
[tex](x-y)\left(y^{2}-4\right)[/tex]
[tex]\text { The product of the given equation is }(x-y)\left(y^{2}-4\right)[/tex]
