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Explain how to graph the given piecewise-defined function. Be sure to specify the type of endpoint each piece of the function will have and why. f(x) = StartLayout enlarged left-brace 1st Row 1st column negative x + 3, 2nd column x less-than 2 2nd row 1st column 3, 2nd column 2 less-than-or-equal-to x less-than 4 3rd Row 1st column 4 minus 2 x, 2nd column x greater-than-or-equal-to 4 EndLayout

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ankitprmr2

Refer the solution for better understanding.

Step-by-step explanation:

Given :

[tex]\left\{\begin{matrix} -x+3 & , & x<2 \\ 3 & , & 2\leq x<4\\ 4-2x & , & x\geq 4\end{matrix}\right.[/tex]

Solution :

The Graph of f(x) = -x + 3 is draw for x less than 2 because x is bounded.

The Graph of f(x) = 3 is draw for x greater than and equal to 2 and less than 4 because x is bounded.

The Graph of f(x) = 4 - 2x is draw for x greater than equal to 4 because x is bounded.

See the attached Graph for more clearity.

f(x) = -x + 3 is represented by purple.

f(x) = 3 is represented by orange.

f(x) = 4 - 2x is reperesented by green.

For more information, refer the link given below

https://brainly.com/question/12561612?referrer=searchResults

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30402018

Answer:

sample response You would graph the equation f(x) = –x + 3 for input values less than 2. There would be an open circle at the point (2, 1) since the domain for the first piece does not include 2. You would then graph a horizontal line at f(x) = 3 for input values between 2 and 4. There would be a closed circle at (2, 3) and an open circle at (4, 3). Last, you would graph f(x) = 4 – 2x for input values greater than or equal to 4. There would be a closed circle at the point (4, –4) since 4 is in the domain of the third piece.

Step-by-step explanation:

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