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A student in Greece discovers a pottery bowl
that contains 21% of its original amount of C-
14.
N = Noe-kt
No = inital amount of C-14 (at time t = 0)
N = amount of C-14 at timet
t = time, in years
k = 0.0001

age of the pottery bowl to the nearest year??

Respuesta :

Answer:

The age of the pottery bowl to the nearest year is 15606 years.

Step-by-step explanation:

Let the initial amount of C-14 in the bowl i.e. [tex]N_{0} = 100[/tex] and today (say after t years) the amount of C-14 in the bowl i.e. N = 21.

Therefore, from the given equation we can write  

[tex]21 = 100 e^{- 0.0001t}[/tex] {Since, k is give to be 0.0001}

⇒ [tex]0.21 = e^{- 0.0001t}[/tex]

Now, taking ln on both sides we get

ln 0.21 = - 0.0001t (ln e) {Since, [tex]\ln a^{b} = b \ln a[/tex]}

⇒ - 1.560647 = - 0.0001t  {We have ln e = 1}

⇒ t = 15606.47 years ≈ 15606 years  

Therefore, the age of the pottery bowl to the nearest year is 15606 years.(Answer)

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