Answer:
The magnitude of the force of gravity between two 1.5 kg flower pots if their separation is 1.0 m is F = 22.05N
Explanation:
To find the magnitude of the force of gravity between two 1.5 kg flower pots if their separation is 1.0 m
We know that force of gravity is given by the formula,
F = [tex]\mathrm{F}=\mathrm{G} \frac{m 1 \mathrm{m} 2}{r * r}[/tex]
Where G is the gravitational constant and = 9.8 m/s
m1 and m2 are masses of given objects which is equal to 1.5 kg given
And r is the distance between the objects given = 1 m
So substituting the values in the formula we get,
F = 22.05N