Answer:
The value of [tex]x=-{\frac{\sqrt{3} }{2} }[/tex]
Step-by-step explanation:
We have to find the value of (x) from the trigonometric equation.
⇒[tex]5arcsin(x)-2\pi =2arcsin(x)-3\pi[/tex]
Subtracting [tex]2arcsin(x)[/tex] and adding [tex]2\pi[/tex] from both sides.
⇒[tex]3arcsin(x)=-\pi[/tex]
Dividing both sides with 3.
⇒[tex]arcsin(x)=\frac{-\pi}{3}[/tex]
Using arcsin(x)=a then x=sin(a) and [tex]sin\frac{\pi}{3} =\frac{\sqrt{3} }{2}[/tex]
So,
⇒[tex]x=sin(\frac{-\pi} {3}) =-\frac{\sqrt{3} }{2}[/tex]
Our final value of (x) =[tex]-\frac{\sqrt{3} }{2}[/tex]
