a student is pushing a 50 kilogram cart with a force of 500 newtons another students measures the speed of the cart and finds that the cart is only accelerating a 4 m/s how much friction must be acting on the cart

Respuesta :

The force of friction is 300 N

Explanation:

We can solve the problem by applying Newton's second law of motion: in fact, the net force acting on an object is equal to the product between the mass of the object and its acceleration. So we can write

[tex]\sum F = ma[/tex]

where

[tex]\sum F[/tex] is the net force acting on the object

m is its mass

a is its acceleration

For the cart in this problem, we have two forces acting on it:

- The force of push, F = 500 N, forward

- The force of friction, [tex]F_f[/tex], backward

So Newton's second law can be rewritten as

[tex]F-F_f = ma[/tex]

where

m = 50 kg

[tex]a=4 m/s^2[/tex] is the acceleration of the cart

And solving for [tex]F_f[/tex], we find the force of friction:

[tex]F_f = F-ma=500-(50)(4)=300 N[/tex]

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