Answer:
[tex]x=-\frac{1-\sqrt{13} }{3} ,-\frac{1+\sqrt{13} }{3}[/tex]
[tex]0.87, -1.54[/tex]
Step-by-step explanation:
[tex]3x^2+2x-4=0[/tex]
Use the quadratic formula:
[tex]x=\frac{-b+\sqrt{b^2-4ac} }{2a} ,\frac{-b-\sqrt{b^2-4ac} }{2a}[/tex]
[tex]x=\frac{-2+\sqrt{2^2-4*3*-4} }{2*3} ,\frac{-2-\sqrt{2^2-4*3*-4} }{2*3}[/tex]
Simplify:
[tex]x=\frac{-2+2\sqrt{13} }{6} ,\frac{-2-2\sqrt{13} }{6}[/tex]
[tex]x=-\frac{1-\sqrt{13} }{3} ,-\frac{1+\sqrt{13} }{3}[/tex]
