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Milliecartier
In a standard deck of cards, there are 13 diamond cards and 39 non diamonds. To choose 3 diamonds from 13 cards would be equivalent to 13*12*11 as there are less cards to choose from each time you remove a card. To choose two non diamonds from the other non diamonds cards would be equivalent to 39*38, taking into account the number of cards you remove each time you pick out one card. Hence the total number of ways is 13x12x11x39x38.

The number of different ways by which can three diamonds and two non-diamonds be dealt from the standard deck of cards is 2543112.

How many cards are there in a deck of card?

There are total 52 cards in a deck of card.

Five cards are dealt from a standard deck of cards. In this, three diamonds and two non-diamonds are dealt.

In a standard deck of cards, there are total 13 diamonds and 39 non-diamond cards. By the rule of product, the ways can be found out as, when the arrangement does not matter,

[tex]x=\;^{13}C_3\times\;^{39}C_2\\x={13\times12\times11}\times {39\times38}\\x=2543112[/tex]

Thus, the number of different ways by which can three diamonds and two non-diamonds be dealt from the standard deck of cards is 2543112.

Learn more about the deck of card here

https://brainly.com/question/5858025

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