Respuesta :
Answer:
B) To maintain peak performance for every 50 generators, there are 10 inspectors.
Step-by-step explanation:
For peak operational:
3 electricians for each generator.  ⇒  1 Generator : 3 Electricians
4 inspectors for every 60 electricians. ⇒  60 Electricians : 4 Inspectors
Now, the number of generators the state has now = 50
Let us assume the number of  inspectors  required by the power plant  = m
Now, from the given ratios:
For, 3 electrician there  is 1 generator
⇒ For, 3 x 20 Electrician  there is 1  x 20 Generators.
or, for 60 Electrician there are 20 Generators. Â (1)
Also, for 60 Electrician there are 4 inspectors. Â Â (2)
⇒From (1) and (2), we get:
For every 20 generators, there are 4 inspectors.
And, from what we have assumed  For every 50 generators, there are m inspectors.
So, by the RATIO OF PROPORTION:
[tex]\frac{20}{4}  = \frac{50}{m}\\ \implies  m = 50 \times\frac{4}{20}  = 10[/tex]
or, m = 10
Hence, to maintain peak performance for every 50 generators, there are 10 inspectors.
Answer:
B) To maintain peak performance for every 50 generators, there are 10 inspectors.
Step-by-step explanation: