The y-intercept is 1/3
I'll assume the function is the following:
[tex]f(x)=-\frac{2}{9}x+\frac{1}{3}[/tex]
As you can see, this is the equation of a line written in Slope-intercept form. The general rule of writing lines in this form is:
[tex]y=mx+b[/tex]
Where [tex]m[/tex] is the slope and [tex]b[/tex] is the y-intercept, which is the point at which [tex]x=0[/tex]. By comparing our function with the written rule, we can say that the y-intercept is:
[tex]\boxed{b=\frac{1}{3}}[/tex]
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Answer:
[tex]b=\frac{1}{3}[/tex]
Step-by-step explanation:
The given function is
[tex]f(x)=-\frac{2}{9}x +\frac{1}{3}[/tex]
This given function is a linear function, because its variables have one as exponent, we can also say that its variables are linear.
This function, as a linear one, it's represented as a line.
Additionally, the form of this function is called slope-intercept form as
[tex]f(x)=mx+b[/tex]
Where [tex]m[/tex] is the slope and [tex]b[/tex] is the y-intercept.
So, in this case
[tex]m=-\frac{2}{9}[/tex] and [tex]b=\frac{1}{3}[/tex]
Therefore, the y-intercept of the given function is
[tex]b=\frac{1}{3}[/tex]
