contestada

1. A rope attaches a tire to an overhanging tree limb. A girl swinging on the tire has a
centripetal acceleration of 3.0 m/s2. If the length of the rope is 2.1 m, what is the girl's
tangential speed?

Respuesta :

Answer:

2.51 m/s

Explanation:

Formula for Centripetal Acceleration

a_{c} =\frac{v^{2} }{r}

where v= velocity of the girl swinging through a rope  and

r=radius of the circle she is moving in ie. the length of the rope assuming its attached till the center of the tire of negligible dimension.

Given

[tex]a_{c} =3.0[/tex] m/[tex]s^{2}[/tex]

r=2.1 m

v=??(in m)

Plugging in the values

3 =\frac{v^{2} }{2.1}

[tex]v^{2}[/tex]=3 × 2.1

[tex]v^{2}[/tex]= 6.3

v=[tex]\sqrt{6.3}[/tex]

v=2.5099 m/s ≈ 2.51 m/s