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An antitank weapon fires a 3.00-kg rocket which acquires a speed of 50.0 m/s after traveling 90.0 cm down a launching tube. Assuming the rocket was accelerated uniformly, what is the average force that acted on it?

Respuesta :

Answer:

Force in the rocket will be 4166.64 N

Explanation:

We have given mass of the rocket m = 3 kg

Rocket acquires a speed of 50 m sec so final speed v = 50 m/sec

Initial speed u = 0 m/sec

Distance traveled s = 90 cm = 0.9 m

From third equation of motion we know that [tex]v^2=u^2+2as[/tex]

[tex]50^2=0^2+2\times a\times 0.9[/tex]

[tex]a=1388.88m/sec^2[/tex]

From newton's law we F = ma

So force will be [tex]F=1388.88\times 3=4166.64N[/tex]

So force in the rocket will be 4166.64 N