Answer: The maximal margin of error is 4.822.
Step-by-step explanation:
Since we have given that
Number of bags = 38
Sample mean = 78 ounces
Standard deviation = 14.5 ounces
At 96% confidence interval for the true population mean bags of nut weight.
So, z = 2.05
As we know that formula for "Margin of error":
[tex]z\times \dfrac{\sigma}{\sqrt{n}}\\\\=2.05\times \dfrac{14.5}{\sqrt{38}}\\\\=4.822[/tex]
Hence, the maximal margin of error is 4.822.
