Answer:
61.76%
Explanation:
Percent yield = Actual yield/Theoeetical yield × 100%
We need to calculate the theoretical yield for this reaction.
Firstly, we need to know the number of moles of hydrogen reacted = mass of hydrogen ÷ molar mass = 450 ÷ 2 = 225 moles
From the reaction, we can see that 3 moles of hydrogen yielded 2 moles of ammonia. Hence 225 moles of hydrogen will yield:
(225 × 2) ÷ 3 = 150 moles
The actual mass of ammonia yielded = number of moles × molar mass = 150 × 17 = 2550g
Actual yield = 1575g
Theoretical yield = 2550g
Percentage yield = 1575/2550 × 100% = 61.76%