The acceleration of the jet is [tex]11.4 m/s^2[/tex]
Explanation:
Since the jet motion is a uniformly accelerated motion (=constant acceleration), we can use the following suvat equation:
[tex]v^2-u^2=2as[/tex]
where
v is the final velocity
u is the initial velocity
a is the acceleration
s is the displacement
For the jet in this problem, we have
u = 0 (it starts from rest)
v = 40 m/s (final velocity)
s = 70 m (length of the runway)
Solving for a, we find the acceleration:
[tex]a=\frac{v-u}{t}=\frac{40^2-0}{2(70)}=11.4 m/s^2[/tex]
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