A coil of 1000 turns encloses an area of 25cm2. It is rotated in 0.010 s from a position where its plane is perpendicular to Earth’s magnetic field to one where its plane is parallel to the field. If the strength of the field is 6.0×10−5T, what is the average emf induced in the coil?

Respuesta :

Answer:

Emf will be 0.015 volt

Explanation:

We have given number of turns N = 1000

Area [tex]A=25cm^2=25\times 10^{-4}m^2[/tex]

Time t = 0.010 sec

Magnetic field [tex]B=6\times 106{-5}T[/tex]

Since plane is perpendicular to the magnetic field so [tex]\Theta =90[/tex]

We know that emf is given by

[tex]e=N\frac{d\Phi }{dt}[/tex]

[tex]e=N\frac{d\Phi }{dt}=N\frac{(BAsin\Theta )}{t}=1000\times \frac{6\times 10^{-5}\times 25\times 10^{-4}sin90^{\circ}}{0.01}=0.015V[/tex]