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An ice block floating in a river is pushed through a displacement d with arrow = (13 m)i hat − (13 m)j along a straight embankment by rushing water, which exerts a force F with arrow = (230 N)i hat − (140 N)j on the block. How much work does the force do on the block during the displacement?

Respuesta :

Answer:

Work done, W = 4810 Joules

Explanation:

Given that,

Force acting on the block, [tex]F=(230i-140j)\ N[/tex]

Displacement in water, [tex]d=(13i-13j)\ m[/tex]

To find,

Work does the force do on the block during the displacement.

Solution,

Let W is the work done by the force on the block. We know that the expression for the work done is given by :

[tex]W=F.d[/tex]

[tex]W=(230i-140j).(13i-13j)[/tex]

We know that,

i.i = j.j = k.k = 1

W = 2990 + 1820

W = 4810 Joules

So, the work done by the force on the block during the displacement is 4810 Joules.

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